a=['/','/aass/dda','/sdfsdf/dsfs/aa/s','/s','/sdf/fd/sdf/f/dsf/sdf/sdf/sd/fs/d']
def takeSecond(elem):
elem.count('/')
a.sort(key=takeSecond)
print (a)
根据list元素包含某个字符的多少对list排序
本文为原创文章，转载请注明出处。
a=['/','/aass/dda','/sdfsdf/dsfs/aa/s','/s','/sdf/fd/sdf/f/dsf/sdf/sdf/sd/fs/d']
def takeSecond(elem):
elem.count('/')
a.sort(key=takeSecond)
print (a)
本文为原创文章，转载请注明出处。
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